XtGem Forum catalog



BASED TECH PORTAL FORUM
FOR ALL


HOME
FORUM
CHATROOM
BLOG
CONTACT
Rules
FAQ
BB Codes
Smilies

Online members: 1


* basedtech Maths Theory Solution

(5a & 5b)
start from the right side for No.5a,b

img

6a)
Sn=n/2(2a+(n-1)d)
A=1, d=2, n=n
Sn=n/2(2*1+(n-1)2)
N/2(2+2,-2)
=n/2*2=n^2
6b)
img

6c)
img

(7a)

x-2/4 :x+2/2x
Cross multiply
2x(x-2)=4(x+2)
Opening the bracket
2x^2-4x = 4x+8
Collect like terms together
2x^2-4x-4x-8=0
2x^2-8x-8=0
Solving with completing the square method
2x^2-8x=8
Divide through with the coefficient of x^2
2x^2/2-8x/2=8/2
X^2-4x=4
Half of coefficient of x
(-4 x 1/2)^2 = (-2)^2
X^2-4x+(-2)^2=4+(-2)^2
X^2-4x+(-2)^2=4+4
(x-2)^2=8
X-2:square root 8
X=2 + or - squar root 8
X=2+ square root 8 or x=2- square root 8
X=2+2.828=4.828
X=2-2.828= -0.828
X=4:83 or - 0.83.

(7B)
img

(8a & 8b)
img

(9a & 9b)
img

(13a & 13b)
img


Please Click on REPLY or QUICK REPLY button below this post to drop your Comment(s), Appreciation(s) or Opinion(s) On this Topic. It'll Help us to improve this information and serve you better.
2016-04-20 10:36 (edited 2016-04-20 23:23 by basedtech ) · (0)

Online: Guests: 1

Like Our Page

Browsing with: Unknown